擅长:python、mysql、java
<p>代码段:</p>
<pre><code>foo = """
address1:= ("a010")
address2:= ("b005")
address3:= ("b030")
address4:= ("b008")
address5:= ("a002")
address6:= ("b004")
"""
import re
pattern = 'address(\d+):= \("b(.*)"\)'
result = re.findall(pattern, foo)
for item in result:
print('{index}: {entry}'.format(index=item[0], entry=item[1]))
</code></pre>
<p>执行输出:</p>
<pre><code>2: 005
3: 030
4: 008
6: 004
</code></pre>