嗨,我有3个列表:在tkinter窗口中的list1 list2和list3 我想这样做:
我想,每次用户按下“回车”后,他完成了条目写作的标签T1将更改为T2和条目将从文本清除 当用户到达T5时,标签SUB1将更改为SUB2,当用户到达T10时,标签SUB2将更改为SUB3,并且对于列表2中的每个值,也将显示列表3中的1个值。谢谢各位,我希望我问的问题很好,而且切中要害 这是我的代码,我试图显示它,但甚至没有打印功能工作时,我按下输入:
import tkinter as tk
from tkinter import ttk
import json
from collections import defaultdict
import pickle
class Language(tk.Tk):
def __init__(self, *args, **kwargs):
tk.Tk.__init__(self, *args, **kwargs)
frame = tk.Frame(self,)
list1 = ["SUB1","SUB2","SUB3"]
list2 = [['T1', 'T2', 'T3', 'T4'], ['T5', 'T6', 'T7', 'T8', 'T9'],
['T10', 'T11', 'T12', 'T13', 'T14', 'T15', 'T16', 'T17']]
list3 = ['rocket', 'file', 'meth', 'pink', 'jelly', 'say', 'east', 'west']
if i > len(list1):
print("the end")
else:
for u in range(len(list1)):
label_sub = tk.Label(self, text=str(list1[i]) + ":", bg="green", )
label_sub.place(x=100, y=150)
for b in range(len(list[u])):
def add(n):
n += 1
return n
if j > len(list2[b]):
i += 1
else:
label_time = tk.Label(self, text=str(list2[b][add(j)]) + ":", bg="green", )
label_time.place(x=0, y=200)
label_word = tk.Label(self, text=str(list3[b]),
bg="green", )
label_word.place(x=150, y=250)
q_entry = tk.Entry(self)
q_entry.bind('<Return>', print("something"))
q_entry.place(x=300, y=200)
root = Language()
root.geometry("612x417")
root.mainloop()
目前没有回答
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