Django网址 - 模板问题 {% url '' %}

Question

当我开始使用Django时，我使用了1.11，然后升级到2.0。我的网址工作，没有任何问题，我可以想象一些东西已经更新，但我一直在看文档，我看不到问题在哪里。据我所知，我在模板中的url是正确的，尽管我也尝试过“”但仍然遇到相同的问题

NoReverseMatch at /admin/dashboard
Reverse for '' not found. '' is not a valid view function or pattern name.
Request Method: GET
Request URL:    http://127.0.0.1:8000/admin/dashboard
Django Version: 2.2.6
Exception Type: NoReverseMatch
Exception Value:    
Reverse for '' not found. '' is not a valid view function or pattern name.
Exception Location: /home/bridgetsarah/.local/lib/python3.5/site-packages/django/urls/resolvers.py in _reverse_with_prefix, line 673
Python Executable:  /usr/bin/python3
Python Version: 3.5.2
Python Path:    
['/home/bridgetsarah/voyage/bridgetsarah',
 '/usr/lib/python35.zip',
 '/usr/lib/python3.5',
 '/usr/lib/python3.5/plat-x86_64-linux-gnu',
 '/usr/lib/python3.5/lib-dynload',
 '/home/bridgetsarah/.local/lib/python3.5/site-packages',
 '/usr/local/lib/python3.5/dist-packages',
 '/usr/lib/python3/dist-packages']
Server time:    Fri, 25 Oct 2019 19:26:43 +0000

如有任何信息，将不胜感激

      <ul>
24      <li> <i class="fas fa-tachometer-alt"></i>  <a href="#"> Dashboard </a> </li>
25      <li><i class="fas fa-tasks"></i>  <a href='#'> Projects </a> </li>
26      <li><i class="fas fa-users"></i> <a href="{% url client %}"> Clients </a> </li>
27      <li><i class="fas fa-server"></i><a href='#'> Servers </a> </li>
28    </ul>  
29  

from django.urls import include, path , re_path
from django.conf.urls import  include, url
from . import views
from django.contrib.auth.views import LoginView
from voyage.views import login_invalid, dashboard, client


app_name = 'voyage'

urlpatterns = [


    # Clients---------------------------------- #
    path('admin/client', views.client, name='client'),]

def client(request):
    return render(request, 'admin/client/client.html', context)

如果有人能给我指出正确的方向，我将不胜感激

Answer 1

它应该是{% url "client" %}—名称必须用引号括起来

注意，这在Django 1.5（2012年）中一直发生了变化；这在版本1.11中肯定不起作用