比较旧dict list和新dict list，找出所有list对象的键和值之间的差异

Question

有很多问题；关于比较直接old dict和new dict的堆栈溢出

• 我想比较一个旧的dict列表和一个新的dict列表，找出删除、添加和更新的内容

old_dict = [{'name':'john','age':10},{'name':'cena','age':26},{'name':'tom','age':24}]
new_dict = [{'name':'cena','age':26},{'name':'john','age':13},{'name':'henry','age':32},{'name':'steave','age':50}]

我想通过old_dict&new_dict作为函数的参数，其中比较所有列表对象中的键、值；该函数将返回以下字段

return updated_key_val,added_key_val,removed_new_key_val

print(updated_key_val)
>> [{'name':'john','age':13}] ### age value updated from 10 to 13

print(added_key_val)
>> [{'name':'henry','age':32},{'name':'steave','age':50}] ## old results doesn't had this 2 dicts so this are new dicts

print(removed_new_key_val)
>> [{'name':'tom','age':24}] ## this has been removed in newer results

Answer 1

因为当“name”字段相等时，每个字典都被认为是相等的，所以您可以为这些条目建立旧名称的索引，然后在对新条目进行一次迭代后跟踪更新、添加和删除的内容

def entries_diff(old_entries, new_entries):
    updated, added = [], []
    old_index = {e['name']: e for e in old_entries}
    for e in new_entries:
        name = e['name']
        if name not in old_index:
            added.append(e)
        else:
            old = old_index[name]
            if old != e:
                updated.append(e)
            del old_index[name]

    removed = list(old_index.values())
    return updated, added, removed

它给出了虚拟数据的预期结果