<p>我的代码有几个问题需要帮助解决</p>
<ol>
<li>如何使标题只在结果上方打印一次,如果没有任何内容符合标准,则根本不打印</李>
<li>我的代码的else组件不再工作了,以前如果其他场景都不是真的,它只会打印,但是我更新了它,现在它每次都会打印。有人能发现这个问题吗</李>
</ol>
<p>代码:</p>
<pre><code>import Hotels
htl_1= Hotels.Hotels(111,100,1,1)
htl_2= Hotels.Hotels(112,200,2,1)
htl_3= Hotels.Hotels(113,250,2,2)
htl_4= Hotels.Hotels(114,300,3,2)
htl_5= Hotels.Hotels(115,350,3,3)
feeInput=input('Enter maximum per night fee: ')
roomInput=input('Enter minimum number of bedrooms: ')
bathInput=input('Enter minimum number of baths: ')
header='{:10} {:10} {:10} {:10}'.format('Room#','Cost','Rooms','Bathrooms')
print(header)
if int(feeInput)>= htl_1.fee and int(roomInput)<= htl_1.rooms and int(bathInput)<= htl_1.bath:
print(htl_1.gethtl())
if int(feeInput)>= htl_2.fee and int(roomInput)<= htl_2.rooms and int(bathInput)<= htl_2.bath:
print(htl_2.gethtl())
if int(feeInput)>= htl_3.fee and int(roomInput)<= htl_3.rooms and int(bathInput)<= htl_3.bath:
print(htl_3.gethtl())
if int(feeInput)>= htl_4.fee and int(roomInput)<= htl_4.rooms and int(bathInput)<= htl_4.bath:
print(htl_4.gethtl())
if int(feeInput)>= htl_5.fee and int(roomInput)<= htl_5.rooms and int(bathInput)<= htl_5.bath:
print(htl_5.gethtl())
else:
print('Sorry, no rooms available that meet that criteria')
</code></pre>