擅长:python、mysql、java
<p>您可以使用<code>.pop(index)</code>获取索引处的值,并通过一个操作将其删除:</p>
<pre><code>numbers = [2,3,4,5,7]
print(numbers)
n = numbers.pop(2)
print (n)
print (numbers)
</code></pre>
<p>输出:</p>
<pre><code>[2, 3, 4, 5, 7]
4
[2, 3, 5, 7]
</code></pre>
<p>索引是基于零的</p>
<p>阅读:
<a href="https://docs.python.org/3.6/tutorial/datastructures.html#more-on-lists" rel="nofollow noreferrer">list.pop([i])</a></p>
<blockquote>
<p>Remove the item at the given position in the list, and return it. If no index is specified, a.pop() removes and returns the last item in the list. (The square brackets around the i in the method signature denote that the parameter is optional, not that you should type square brackets at that position. You will see this notation frequently in the Python Library Reference.)</p>
</blockquote>