如果字符串中的字母是辅音，则将字母加倍并在中间加上“o”，否则加上“n”

Question

我想解决一个问题，这个问题要求我用一个句子，把每个辅音翻一番，中间加个“o”

我知道可以在一行中使用if语句，但是else语句不起作用

vowels = list('aeiouyäöå')
consonants = list('qwrtpsdfghjklzxcvbnm')


# if letter is a consonant then double it and out 'o' in between.
def rovarspraket(sentence):
    return ''.join([letter for letter in sentence if letter in vowels else (letter + 'o' + letter)])

print(rovarspraket('hello friend'))
# should output 'hohelollolo fofrorienondod'.

Answer 1

空间也很重要：

return ''.join(letter if letter in vowels or letter == ' ' else (letter + 'o' + letter)for letter in sentence)

所以，代码：

vowels = list('aeiouyäöå')
consonants = list('qwrtpsdfghjklzxcvbnm')


# if letter is a consonant then double it and out 'o' in between.
def rovarspraket(sentence):
    return ''.join(letter if letter in vowels or letter == ' ' else (letter + 'o' + letter)for letter in sentence)

print(rovarspraket('hello friend'))

输出：

hohelollolo fofrorienondod

Answer 2

条件理解中else部分的语法有点错误：

def rovarspraket(sentence):
    return ''.join([l if l in vowels else (l + 'o' + l) for l in sentence])

或者更好（更强大的wrt空白）：

def rovarspraket(sentence):
    return ''.join([(l + 'o' + l) if l in consonants else l for l in sentence])

>>> print(rovarspraket('hello friend'))
hohelollolo fofrorienondod