擅长:python、mysql、java
<p>在@anubhavva的帮助下,我构建了这个通用函数:</p>
<pre><code>def replace_in_word(replace_in, replace_what, replace_with):
#in string replace_in, replace_what with replace_with, and return the string
#but only inside a word
#if not found, return unchanged string
return(re.sub(r"\b%s\b" % replace_what, replace_with, replace_in))
</code></pre>