擅长:python、mysql、java
<p>我觉得您提供的示例字符串不需要任何正则表达式:</p>
<pre><code>temp2 = '(LEFT-WALL)(who)(is.v)(the)(di(rect)or.n)(of)(Inceptio)(RIGHT-WALL)'
if temp2[0:1] == "(" and temp2[-1:] == ")":
print temp2[1:-1].split(")(")
</code></pre>
<p><a href="http://goo.gl/xzA6hi" rel="nofollow">sample program</a>的输出:</p>
<pre><code>['LEFT-WALL', 'who', 'is.v', 'the', 'di(rect)or.n', 'of', 'Inceptio', 'RIGHT-WALL']
</code></pre>