擅长:python、mysql、java
<p>可以在列表中使用<a href="https://docs.python.org/2/library/functions.html#zip" rel="nofollow">^{<cd1>}</a>函数:</p>
<pre><code>>>> l=['...','name','anbc','date','20/02/2001','path0', 'd://nk/mkn','path1'
... 'k//lk/jjj','path2','f//udfg/jki','path3','hjk//de/lk']
>>> [(i,j) for i,j in zip(l,l[1:]) if i.startswith('path')]
[('path0', 'd://nk/mkn'), ('path1k//lk/jjj', 'path2'), ('path2', 'f//udfg/jki'), ('path3', 'hjk//de/lk')]
</code></pre>