布尔控制流变量未正确实现

Question

我有下面的代码，但是当playing=false时，它不能控制流以允许player2掷骰子。有人能发现错误吗？基本上，它从来没有得到：滚轴骰子2和我不知道为什么

注意：我在RollTwoDiceP1中尝试将playing（布尔变量）设置为false，希望在返回playerturns（）函数时，这次将转到RollTwoDiceP2（Player2 turn sub）。那不行

    def callmatrix(player1,player2, n):
    print("*************LOADING GAME******************")
    print("Welcome:", player1,"and", player2)
    for i in matrix(n):
            print(i)
    playing = True
    playerturns(player1,player2,playing)

def playerturns(player1,player2,playing):
    print(" - - - - - - - - - - ")
    print("Press Enter to contnue")
    #playing = True
    while(playing):     
        roll=input()
        if roll=="r" or "R":
            RollTwoDiceP1(player1,player2)
        else:
            RollTwoDiceP2(player1,player2)


def RollTwoDiceP1(player1,player2):
    turn=input("Player 1, it's your turn to roll the dice: Press r to roll:>>>")
    #create two variables here and assign them random numbers
    die1=random.randint(1,6)
    die2=random.randint(1,6)

    #add the two die numbers together
    roll=die1+die2

    #when you are printing an integer, you need to cast it into a string before you printit
    print("Player1: You rolled a:", die1, "and a", die2, "which give you a:", roll)

    playing = False
    playerturns(player1,player2,playing)

def RollTwoDiceP2(player1,player2):
    turn=input("Player 2, it's your turn to roll the dice: Press r to roll:>>>")
    #create two variables here and assign them random numbers
    die1=random.randint(1,6)
    die2=random.randint(1,6)

    #add the two die numbers together
    roll=die1+die2    


    print("Player2: You rolled a:", die1, "and a", die2, "which give you a:", roll)

    playing = True
    playerturns(player1,player2,7,playing)

输出：

Continually asks Player 1 to Roll. Prints the result of Player 1s roll (repeat)

这是一个逻辑错误，因此它不是指定问题的重复

Answer 1

问题是行if roll=="r" or "R":。首先，我们计算roll=="r"，它可能是真的，也可能是假的，然后是"R"，它总是真的。因为它与一个or组合在一起，所以语句总是true，else分支不会被执行。将语句更改为if roll == "r" or roll == "R":或更好的if roll.lower() == "r":