如何让我的骰子游戏停止给我错误时，使用随机数

Question

它一直给我语法错误在突出地区请有人告诉我为什么我得到他们this image shows you the code that i have used and highlighted areas where i get a syntax error

如果链接不起作用，这里的代码没有突出显示的区域：

goes = 3
while True:
    import random
    die1 = 0
    die2 = 0
    die3 = 0
    die1 = str(random.randint(1,6))
    die2 = str(random.randint(1,6))
    die3 = str(random.randint(1,6))

    if die1 == die2 == die3:
        print(die1+die2+die3)

    if die1 == die2 not die3:
        print(die1+die2-die3)

    if die1 == die3 not die2:
        print(die1+die3-die2)

    if die2 == die3 not die1:
        print(die2+die3-die1)

    else:
        print(0)
    goes=goes-1
    if goes < 1:
        break

    print ([die1],[die2],[die3])

Answer 1

die1 == die2 not die3没有任何意义。我猜你的意思是：

die1 == die2 and not (die1 == die3)

或者更简单地说：

die1 == die2 and die1 != die3

因为我们已经检查了三者是否相等，所以我们可以通过使用elif避免后面的比较：

if die1 == die2 == die3:
    print(die1+die2+die3)
elif die1 == die2:
    print(die1+die2-die3)
elif die1 == die3:
    print(die1+die3-die2)
elif die2 == die3:
    print(die2+die3-die1)

所以如果代码达到elif die1 == die2:，这意味着die1 == die2 == die3是假的