Python：在列表中分隔术语并赋值

Question

我使用了一个关键字提取器，得到了如下列表-

[('solutions design team', 0.5027793039863974), 
('communication skills', 0.039048703166463736), 
('internal stakeholders', 0.03230578820017667),
('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]

我试图将这些单词分开，并分别为每个单词指定相应的值（在右边给出）

例如，将“解决方案设计团队”=0.5027793039863974转换为

'solutions' = 0.5027793039863974, 
'design' = 0.5027793039863974 ,   
'team' = 0.5027793039863974.

Answer 1

如何使用双平面理解重新创建一个元组列表，其中包含分隔的单词：

inlist = [('solutions design team', 0.5027793039863974),
('communication skills', 0.039048703166463736),
('internal stakeholders', 0.03230578820017667),
('potential customers', 0.020380881551651655), ('utilize', 0.002776174060064261)]

outlist = [(word,value) for words,value in inlist for word in words.split()]

结果：

>>> outlist
[('solutions', 0.5027793039863974),
 ('design', 0.5027793039863974),
 ('team', 0.5027793039863974),
 ('communication', 0.039048703166463736),
 ('skills', 0.039048703166463736),
 ('internal', 0.03230578820017667),
 ('stakeholders', 0.03230578820017667),
 ('potential', 0.020380881551651655),
 ('customers', 0.020380881551651655),
 ('utilize', 0.002776174060064261)]

请注意，如果关键字出现多次，则元组列表中会有重复的关键字。如果您想累积它们，collections.defaultdict(float)对象可以方便地创建关键字=>；的字典；累积值

accumulated = collections.defaultdict(float)
for word,value in outlist:
    accumulated[word] += value