在具有奇数项的迭代过程中，在同一行上打印dict的值和下一个值

Question

（Python2.7）在前面的问题中，我试图遍历字典“rooms”的键，并且每行只显示两个键，如何一次显示奇数个房间？更具体地说，每条线两个，直到只剩下一个，并且只有那一个会自己走上一条线

Previous Question

当前代码：

rooms = {
"101": "Classroom",
"102": "Bathroom",
"103": "Room",
"104": "Room",
"105": "Room",
"106": "Room"}


keys = iter(sorted(rooms.keys()))
for key in keys:
    print key + "    " + next(keys)

电流输出：

101    102
103    104
105    106

目标输出：

101    102
103    104
105    106
107

Answer 1

^{}接受第二个可选参数作为默认值，在迭代器耗尽时返回

keys = iter(sorted(rooms.keys()))
for key in keys:
    print key + "    " + next(keys, "")

Answer 2

rooms = {
"101": "Classroom",
"102": "Bathroom",
"103": "Room",
"104": "Room",
"105": "Room",
"106": "Room",
"107": "Room"}


keys = iter(sorted(rooms.keys()))
for key in keys:
    try:
        print(key + "    " + next(keys))
    except StopIteration:
        print(key)

不过，把keys列成一个列表，然后检查是否已经到了结尾，可能要简单得多

Answer 3

或者使用enumerate

from __future__ import print_function

per_line = 2
keys = iter(sorted(rooms.keys()))
for i, key in enumerate(keys):
    if (i + 1) % per_line == 0 or (i + 1) == len(rooms.keys()):
        print(key)
    else:
        print(key, end="\t")