在列表中使用'if'变量

Question

我知道这将是非常具体的，甚至可能问过之前，但我找不到任何可以帮助我与它。我正在尝试创建一种类似于“文件，请”的游戏，并且在同时使用“如果”变量和列表时遇到困难

这是我的密码：

import time
import random

#Variables

NAT = ["British","American","French","Spanish","Italian"]

GEN = ["M","F"]
if GEN == "M":
    FN = ["Greg","Harvey","Joseph","Prabesh","John","Joe"]
elif GEN == "F":
    FN = ["Emma","Olivia","Sophia","Ava","Georgia","Nia"]

LN = ["Sutton","Little","Mayers","Pearce","Fagu","Smith"]
D = list(range(1,28))
M = ["Jan","Feb","March"]
Y = list(range(1900,1975))

#Design

def passport():
    global NAT
    global FN
    global GEN
    print(" __________")
    print("|-PASSPORT-|")
    print("|Nationality:",random.choice(NAT))
    print("|Gender:",random.choice(GEN))
    print("|First Name:",random.choice(FN))
    print("|Last Name:",random.choice(LN))
    print("|D.O.B:",random.choice(D),random.choice(M),random.choice(Y))


passport()

在我加入性别变量之前，一切都很顺利。我得到的错误是：

Traceback (most recent call last):
  File "C:/Users/Greg/AppData/Local/Programs/Python/Python37-32/Games.py", line 60, in <module>
    passport()
  File "C:/Users/Greg/AppData/Local/Programs/Python/Python37-32/Games.py", line 55, in passport
    print("|First Name:",random.choice(FN))
NameError: name 'FN' is not defined
>>> 

任何帮助都将不胜感激，因为我不知道从这里去哪里。很抱歉让你很痛苦：）

Answer 1

GEN在if语句运行时具有值["M", "F"]。这意味着GEN与语句case不匹配，因此FN从未定义

您可能希望函数选择名字，以便在运行时传递所选的性别

Answer 2

其他人说变量FN没有定义，在if GEN == "M":之前最好这样定义FN：

FN = []
if GEN == "M":
# And so on ...

Answer 3

您可以定义以下内容：

GEN = ["M","F"]

因此，这两个if/elif语句都失败（因为["M","F"] != "M"和["M","F"] != "F"）：

if GEN == "M":
    FN = ["Greg","Harvey","Joseph","Prabesh","John","Joe"]
elif GEN == "F":
    FN = ["Emma","Olivia","Sophia","Ava","Georgia","Nia"]

因此，FN是未定义的