new = {('E_1E_2', 1.0235591568933329): [datetime.datetime(2019, 6, 25, 4, 38, 47)],
('E_1E_2', 0.9023917716540885): [datetime.datetime(2019, 6, 25, 4, 38, 51)],
('E_12E_2', 1.4927612857980848): [datetime.datetime(2019, 6, 25, 3, 18, 42)],
('E12_1E_2', 1.0235591568933329): [datetime.datetime(2019, 6, 25, 3, 30, 17)],
('E_1E_2', 0.9023917716540885): [datetime.datetime(2019, 6, 25, 3, 13, 51)],
('E_1E_2', 1.4927612857980848): [datetime.datetime(2019, 6, 25, 3, 8, 42)]}
我的数据输入就是这样的。我需要以小时为单位显示学生完成任务所用的时间。字典键由执行任务的学生对和两个学生对之间的距离组成。该值由它们彼此接近的时间戳组成
tasktime=0
prev=datetime.datetime(1,1,1)
for i,j in new.items():
#print(k[0],k[1])
print(i[0],"-------------------------------------------------")
for k,l in new.items():
if i[0]==k[0]:
if k[1] < 1 and len(l)==1 and j[0].hour==l[0].hour:
print("distance=======",k[1])
print(l[0].hour,i[0],l)
if (k[0],l[0]) not in sample.keys():
sample[k[0],l[0].hour]=0
if prev==datetime.datetime(1,1,1):
prev=l[0]
else:
diff=(l[0]-prev).seconds
tasktime=tasktime+diff
prev=l[0]
elif loitime!=0 and k[1] > 1:
print(k[0],"loitered for ",tasktime/60,"minutes")
print("timestamp ++++++++++++++++",l[0])
我得到的时间,他们为整个数据的任务,而不是每小时的基础上
目前没有回答
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