如何使用BeautifulSoup刮取超链接标题？

Question

所以，我想从这个网站上搜刮：https//viewyourdale gabrielsimone.com'

产品名称和价格在每个div class=“info wrapper”下 我可以提取价格没有问题，但当我试图提取产品标题，它不能转换成文本作为其a href链接。每个产品名称都位于href下的div类下。 所以我的问题是，我如何刮产品名称

import json
from bs4 import BeautifulSoup
import requests 
import csv
from datetime import datetime

url = 'https://viewyourdeal-gabrielsimone.com'

gmaInfo=[]
response = requests.get(url, timeout=5)
content = BeautifulSoup(response.content, "html.parser")
for info in content.findAll('div', attrs={"class" : "wrapper ease-animation"}):
    gridObject = {
            "title" : info.find('div', attrs={"class" : "title animation allgrey"}),
            "price" : info.find('span', attrs={"class":"red-price"}).text
            }
    print(gridObject)
    with open('index.csv', 'w') as csv_file:
        writer = csv.writer(csv_file)
        writer.writerow([gridObject])

Answer 1

我对我的div类太具体了，我把类改成了简单的标题，效果很好

Answer 2

在下面的代码中，很少有项返回为None。只需提供If条件If元素exists获取文本

from bs4 import BeautifulSoup
import requests
import csv
from datetime import datetime

url = 'https://viewyourdeal-gabrielsimone.com'

gmaInfo=[]
response = requests.get(url, timeout=5)
content = BeautifulSoup(response.content, "html.parser")

for info in content.findAll('div', attrs={"class" : "wrapper ease-animation"}):
   if info.find('div', attrs={"class": "title animation allgrey"}):
     gridObject = {
            "title" : info.find('div', attrs={"class" : "title animation allgrey"}).text.strip(),
            "price" : info.find('span', attrs={"class":"red-price"}).text
            }
     print(gridObject)
     with open('index.csv', 'w') as csv_file:
        writer = csv.writer(csv_file)
        writer.writerow([gridObject])