<p>我想知道为什么代码不能识别10/11的字段值在list['10','11']中,以及为什么它会绕过初始if语句</p>
<p>任何可能的解决方案都会非常感激,代码下面还有运行代码后生成的print语句</p>
<pre><code> TableRow = DBSelect.fetchall()
for Field in TableRow:
print(Field, "This is the currently looped ID")
print(EList, "This is the EList")
if Field in EList : # compares each ID against the EList
print(EList, "This is pre- modified EList")
EList.pop([Field]) # removes the ID from EList
print(EList, "This is post- modified EList")
UnavailableE = UnavailableE + 1 #Add to the number of unavailable E
print(UnavailableE, "This is the Unavailable e in the loop")
elif UnavailableE == ECount: # if the UnavailableE is Equal to ECount, then no ID available - runs this output
print("No e available")
else:
print("Not in list")
</code></pre>
<p>为进一步参考,以下是由此产生的打印语句:</p>
<p>10这是当前循环的ID</p>
<p>['10','11']这是EList</p>
<p>不在列表中</p>
<p>11这是当前循环的ID</p>
<p>['10','11']这是EList</p>
<p>不在列表中</p>