用嵌套lis连接列表

Question

a = [1, 2]
b = [[5,6], [7,8]]
c = list(zip(a, b))
print("c zipped:", c)
i = 0
lenghta = len(a)
c = []
while i < lengtha:
    temp_list = [a[i], b[i]]
    c.append(temp_list)
    i += 1
print("c: ", c)

输出：

c zipped: [(1, [5, 6]), (2, [7, 8])] c:  [[1, [5, 6]], [2, [7, 8]]]

我期待的是：

[[1, 5, 6], [2, 7, 8]]

Answer 1

使用zip和list comprehension

a = [1, 2]
b = [[5,6], [7,8]]

[[i]+j for i,j in zip(a,b)]
#[[1, 5, 6], [2, 7, 8]]

Answer 2

我知道这不是使用zip()，但是您可以：

c = []
for i in range(len(a)):
    c.append([a[i], b[i]])

Answer 3

这似乎过于复杂了。尝试使用list comprehension：

a = [1, 2]
b = [[5,6], [7,8]]

c = [[x] + b[i] for i, x in enumerate(a)]