在python中将元素拆分为新列表

Question

我的清单如下：

['Jeoe Pmith H 158.50\n', 'Ppseph Ksdian h 590.00\n', 'll Mos K 89.0\n', 'Wncy Bwn  j -97.0\n', 'May KAss S  33.58\n', 'Ai Hami s 670.0\n', 'Age Karn J 674.50\n', 'Loe AIUms s 87000.0\n', 'karl Marx J 67400.9\n', 'Joeh Stig S 34.8\n']

如何将此列表中的元素拆分为3个新列表，如下所示：

[' Jeoe Pmith', 'Ppseph Ksdian', ....'Joeh Stig']

['H' , 'h', 'K', .....'S']

['158.50', '590.00'....'34.8'] #(for this list, getting rid of \n as well)

谢谢你

Answer 1

L = ['Jeoe Pmith H 158.50\n', 'Ppseph Ksdian h 590.00\n', 'll Mos K 89.0\n', 'Wncy Bwn  j -97.0\n', 'May KAss S  33.58\n', 'Ai Hami s 670.0\n', 'Age Karn J 674.50\n', 'Loe AIUms s 87000.0\n', 'karl Marx J 67400.9\n', 'Joeh Stig S 34.8\n']

L = [s.strip().rsplit(None,2) for s in L]
first = [s[0] for s in L]
second = [s[1] for s in L]
third = [s[2] for s in L]

输出：

In [10]: first
Out[10]: 
['Jeoe Pmith',
 'Ppseph Ksdian',
 'll Mos',
 'Wncy Bwn',
 'May KAss',
 'Ai Hami',
 'Age Karn',
 'Loe AIUms',
 'karl Marx',
 'Joeh Stig']

In [11]: second
Out[11]: ['H', 'h', 'K', 'j', 'S', 's', 'J', 's', 'J', 'S']

In [12]: third
Out[12]: 
['158.50',
 '590.00',
 '89.0',
 '-97.0',
 '33.58',
 '670.0',
 '674.50',
 '87000.0',
 '67400.9',
 '34.8']