擅长:python、mysql、java
<blockquote>
<p><code>for phoneNumber, PhoneOwner, Frequency in dict.iteritems():</code></p>
</blockquote>
<p>您正试图将两个值(<code>dict.itertimes()</code>返回2元组)解压为3个变量。相反,您应该首先迭代外部dict,然后计算嵌套dict:</p>
<pre><code>for phoneNumber, inner_dict in phonenumbers.iteritems():
if inner_dict['Frequency'] == 0:
print str(phoneNumber) + inner_dict['PhoneOwner']
</code></pre>