擅长:python、mysql、java
<p>另一种方法是使用内置方法<a href="https://docs.python.org/2/library/functions.html#filter" rel="nofollow">filter</a>,根据条件(<code>sub_d[Frequency]==0</code>)过滤字典,方法如下:</p>
<pre><code>>>> d
{17733124060L: {'Frequency': 0, 'PhoneOwner': u'Bob'}, 18444320742L: {'Frequency': 0, 'PhoneOwner': u'Jane'}, 18444320737L: {'Frequency': 1, 'PhoneOwner': u'Sarah'}}
>>> for i in filter(lambda s:d[s]['Frequency']==0, d):
print '%d %s' % (i, d[i]['PhoneOwner'])
17733124060 Bob
18444320742 Jane
</code></pre>