如何让用户输入一个数字，从当前列表中选择该项并将其添加到新列表中？

Question

我正在做一个快速的游戏，只是为了好玩，只是学习代码，我似乎无法摆脱这个问题

set1 = ["Horse", "Cow", "Pig", "Goat", "Chicken", "Sheep", "Donkey", "Duck", "Rabbit"]
set2 = ["Horse", "Cow", "Pig", "Goat", "Chicken", "Sheep", "Donkey", "Duck", "Rabbit"]
random.shuffle(set1,random.random)
random.shuffle(set2,random.random)
side1 = int(input("What number would you like to pick from side one?"))
side2 = int(input("What number would you like to pick from side two?"))
s1pick = set1.index(side1)
s2pick = set2.index(side2)
picks = []

我希望他们为side1和side2输入2个数字，然后将set1和set2中的相应值存储在s2pick和s1pick中。但我一直收到这样的错误信息：

Traceback (most recent call last):
    File "C:/Users/Me/PycharmProjects/nice memes/src/snap.py", line 26, in <module>
        s1pick = set1.index(side1)
ValueError: 4 is not in list

在pycharm社区版上使用python3。谢谢

Answer 1

^{}返回传递给它的元素值的索引。所以对于列表l = ['a', 'b', 'c']，l.index('b')将返回1

如果要转到另一个方向，获取索引的值，则应使用项访问语法：

>>> l = ['a', 'b', 'c']
>>> l[1]
'b'

因此，在您的例子中，您希望使用set1[side1]，以便获得用户从set1中选择的值