不循环搜索数据帧中的文本列

2024-05-19 08:37:03 发布

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我有一个pandas数据框,其中一列是文本描述字符串。我需要创建一个新的列来标识列表中的一个字符串是否在文本描述中

df = pd.DataFrame({'Description': ['2 Bedroom/1.5 Bathroom end unit Townhouse.  
Available now!', 'Very spacious studio apartment available', ' Two bedroom, 1 
bathroom condominium, superbly located in downtown']})

list_ = ['unit', 'apartment']

那么结果应该是

                                        Description    in list
0  2 Bedroom/1.5 Bathroom end unit Townhouse.  Av...    True
1           Very spacious studio apartment available    True
2   Two bedroom, 1 bathroom condominium, superbly...   False

我可以这样做

for i in df.index.values:
    df.loc[i,'in list'] = any(w in df.loc[i,'Description'] for w in list_)

但是对于一个大的数据集,它需要的时间比我想的要长


Tags: 数据字符串in文本dfunitdescriptionlist
2条回答

通过使用str.contains

list_ = ['unit', 'apartment']
df.Description.str.contains('|'.join(list_))
Out[724]: 
0     True
1     True
2    False
Name: Description, dtype: bool

使用np.char.find-

v = df.Description.values.astype('U')[:, None]
df['in list'] = (np.char.find(v, list_) > 0).any(1)

df

                                         Description  in list
0  2 Bedroom/1.5 Bathroom end unit Townhouse.  Av...     True
1           Very spacious studio apartment available     True
2   Two bedroom, 1 bathroom condominium, superbly...    False

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