擅长:python、mysql、java
<p>在</p>
<pre><code>if char == aStr[iMid] or char == aStr: #iMid is not being interpreted as an integer
</code></pre>
<p><code>iMid</code>不是整数。这是函数</p>
<p>您需要调用函数来获取它返回的整数</p>
<pre><code>if char == aStr[iMid(aStr)] or char == aStr: #iMid is called and returns an integer
</code></pre>