<p>如果给定的数字小于2,它会要求使用递归重新输入数字</p>
<p>我首先给出了2,然后在递归之后,我给出了3,但是输出仍然是2</p>
<p>如何输出3</p>
<pre><code>def inexpno():
exp = int(input("Enter the Experiment n.o : ")) # Takes a exp number
if exp<=2: # Enter your completed experiment here
print("It is completed Correction for both Record and Observation\n\n")
print("Do you want to select another experiment")
we = input("")
if we == "yes" or we == "YES":
inexpno() # TO CHANGE
else:
exit()
return exp
print(inexpno())
</code></pre>