擅长:python、mysql、java
<p>在我看来,最好的方法是使用<code>try</code>/<code>except</code>子句将字符串强制转换为<code>float</code>:</p>
<blockquote>
<pre><code>"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true
" -90e3 " => true
" 1e" => false
"e3" => false
" 6e-1" => true
" 99e2.5 " => false
"53.5e93" => true
" 6 " => false
"-+3" => false
"95a54e53" => false
</code></pre>
</blockquote>
<hr/>
<p>让我们用上面的字符串生成一个列表:</p>
<pre><code>l = ["0", " 0.1 ", "abc", "1 a", "2e10", " -90e3 ", " 1e", "e3",
" 6e-1", " 99e2.5 ", "53.5e93", " 6 ", "-+3", "95a54e53"]
def is_number(s):
try:
float(s)
return True
except ValueError:
return False
list(map(is_number, l))
# [True, True, False, False, True, True, False, False, True, False,
# True, False, False, False]
</code></pre>