擅长:python、mysql、java
<p>使用<a href="https://docs.python.org/2/library/itertools.html#recipes" rel="nofollow">^{<cd1>} recipe from ^{<cd2>}</a>:</p>
<pre><code>>>> L
[1, 2, 3, 4, 5, 6]
>>> zip(*grouper(L, 3))
[(1, 4), (2, 5), (3, 6)]
</code></pre>
<p>拉链里面有元组。如果出于某种原因需要列表,请理解:</p>
<pre><code>>>> [list(t) for t in _]
[[1, 4], [2, 5], [3, 6]]
</code></pre>