从lis中删除所有出现的字符串

Question

有人请告诉我有一个更干净的方法写这个！？我要删除“Features&；的所有实例”；“好处”。对于列表中的字符串，必须有一种更干净的方法

lov_headers = [x.find('displayname').text for x in soup.find_all('attributedefinition')]


if 'Part number' in lov_headers:
    lov_headers.remove('Part number')
if 'Product Features' in lov_headers:
    lov_headers.remove('Product Features')
if 'Packaging' in lov_headers:
    lov_headers.remove('Packaging')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')
if 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')

Answer 1

可以使用while循环：

while 'Features & Benefits' in lov_headers:
    lov_headers.remove('Features & Benefits')

Answer 2

将要删除的内容放入set()，然后使用列表理解筛选出不需要的结果：

to_remove = set(['Part number', 'Features & Benefits', 'Product Features', 'Packaging'])

new_list = [i for i in lov_headers if i not in to_remove]