在python中导入2个字典列表和嵌套键/值对

Question

我有两个json，它们是字典列表，我想用它们在python中创建第三个json

第一个json是姓氏.json

[{
    "lastnameID": "1",
    "name": "Doe"
}, {
    "lastnameID": "2",
    "name": "Smith"
}]

第二个json是名字.json

[{
    "firstnameID": "1",
    "name": "John",
    "lastnameID": "1"
}, {
    "firstnameID": "2",
    "name": "Jane",
    "lastnameID": "1"
}, {
    "firstnameID": "3",
    "name": "Bob",
    "lastnameID": "2"
}, {
    "firstnameID": "4",
    "name": "Mary",
    "lastnameID": "2"
}]

我希望我的输出是output.json

[{
    "lastnameID": "1",
    "name": "Doe",
    "first names": [{
        "firstnameID": "1",
        "name": "John"
    }, {
        "firstnameID": "2",
        "name": "Jane"
    }]
}, {
    "lastnameID": "2",
    "name": "Smith",
    "first names": [{
        "firstnameID": "3",
        "name": "Bob"
    }, {
        "firstnameID": "4",
        "name": "Mary"
    }]
}]

如何在python3上实现这一点

我在下面试过，但一定有比这更好的办法

import json

finaljson = []
with open('first_names.json', 'r') as f:
    firstnames = json.load(f)
with open('last_names.json', 'r') as f:
    lastnames = json.load(f)
for i in range (0, len (lastnames)):
    firstnamelist = []
    lastnameID = lastnames[i]['lastnameID']
    lastname = lastnames[i]['name']
    for i in range (0, len (firstnames))
        if firstnames[i]['lastnameID'] == lastnameID:
            firstname = firstnames[i]['name']
            firstnameID = firstnames[i]['firstnameID']
            firstnamelist.append("firstnameID":firstnameID,"name":firstname)
    finaljson.append({"lastnameID":lastnameID,"name":lastname,"firstnames":firstnamelist})

Answer 1

词典内

for first_ in first:
    first_['first names'] = [{x:y for x, y in second_.items() if x == 'firstnameID' or x == 'name'} 
                             for second_ in second if second_['lastnameID'] == first_['lastnameID']]

print (first)      

请查看以下结果：

[{'lastnameID': '1', 'name': 'Doe', 
      'first names': [{'firstnameID': '1', 'name': 'John'}, 
                      {'firstnameID': '2', 'name': 'Jane'}]}, 
 {'lastnameID': '2', 'name': 'Smith', 
      'first names': [{'firstnameID': '3', 'name': 'Bob'}, 
                      {'firstnameID': '4', 'name': 'Mary'}]}]