擅长:python、mysql、java
<p>这是你的解决办法</p>
<pre><code>#v1='2132' v2='L' v3='Y'
def Solution(v1,v2,v3):
if v1 in dict1.keys():
for i in dict1[v1]:
if v2 in i.keys():
if v3 in i[v2]:
return i[v2][v3]
return None
dict1 = {'2132': [{'L': {'Y': '452.2'}}, {'C': {'N': '21'}}], '2345': [{'L': {'Y': '87'}}, {'C': {'N': '56'}},{'6': {'Y': '45.23'}}]}
print(Solution('2132','L','Y'))
</code></pre>