如何将一个模型实例作为JSON返回给android端的GSON进行反序列化？

Question

我有一个django rest框架GenericAPIView：

class ListUnseenFriendRequests(generics.GenericAPIView):
    permission_classes = (IsAuthenticated,)

    def get(self, request, format=None):
        friendship_requests_list = Friend.objects.unread_requests(user=request.user)
        friendship_requets_dict = [friend_request_as_json(obj) for obj in friendship_requests_list]
        return Response(json.dumps(friendship_requets_dict), content_type="application/json")

ListUnseenFriendRequests应该返回发出请求的用户的所有好友的列表。我不确定这是否是将FriendshipRequest对象返回为json的最佳/最简单的方法，如果有更好的方法请告诉我

我还使用了2个助手方法friend_request_as_json和user_as_json：

def friend_request_as_json(obj):
    return dict(
        id=obj.id, 
        from_user=user_as_json(obj.from_user), 
        created=str(obj.created))

def user_as_json(obj):
    return dict(
        id=obj.id,
        email=obj.email,
        firstName=obj.firstName,
        lastName=obj.lastName)

使用postman测试ListUnseenFriendRequests视图这是我得到的：

"[{\"created\": \"2017-08-02 09:06:54.272168+00:00\", \"id\": 29, 
\"from_user\": {\"lastName\": \"Graham\", \"email\": \"joe@gmail.com\", \"firstName\": \"Joe\", \"id\": 5}}]"

为什么有这么多反斜杠？有区别吗

在客户端，我使用reformation和GSON来反序列化。客户端上保存此响应数据的模型是FriendRequestResponse：

public class FriendRequestResponse {

    @SerializedName("id")
    @Expose
    private int id;

    @SerializedName("from_user")
    @Expose
    private User fromUser;

    @SerializedName("created")
    @Expose
    private String createdAt;

    public FriendRequestResponse(int id, User fromUser, String createdAt) {
        this.id = id;
        this.fromUser = fromUser;
        this.createdAt = createdAt;
    }

    public int getId() {
        return id;
    }

    public User getFromUser() {
        return fromUser;
    }

    public String getCreatedAt() {
        return createdAt;
    }
}

User模型：

public class User {

    @SerializedName("id")
    @Expose
    private int id;

    @SerializedName("email")
    @Expose
    private String email;

    @SerializedName("firstName")
    @Expose
    private String firstName;

    @SerializedName("lastName")
    @Expose
    private String lastName;

    @SerializedName("date_joined")
    @Expose
    private String dateJoined;

    private String password;

    public User(String email, String firstName, String lastName, String password) {
        this.email = email;
        this.firstName = firstName;
        this.lastName = lastName;
        this.password = password;
    }

    public int getId() { return id; }

    public String getEmail() {
        return email;
    }

    public String getFirstName() {
        return firstName;
    }

    public String getLastName() {
        return lastName;
    }

    public String getPassword() {
        return password;
    }

    public String getDateJoined() {
        return dateJoined;
    }
}

这个模型的结构是否正确，可以接受json并适合它

Answer 1

您已经有了JSON，您正试图将其作为JSON转储

请尝试使用以下选项：

return Response(json.loads(friendship_requets_dict), content_type="application/json")