使用execfi运行带有闭包的脚本时未定义全局名称

Question

我正在尝试从带有execfile的script1运行script2，并且script2包含闭包：

script1.py

MyVar1 = 'value1'


def fun1():
    print(MyVar1)


def fun2():
    execfile('script2.py')

fun1()
fun2()

script2.py

MyVar2 = 'value2'


def fun1():
    print(MyVar2)


fun1()

出现错误

  File "...script1.py", line 12, in <module>
    fun2()
  File "...script1.py", line 9, in fun2
    execfile('script2.py')
  File "script2.py", line 8, in <module>
    fun1()
  File "script2.py", line 5, in fun1
    print(MyVar2)
NameError: global name 'MyVar2' is not defined

如何修复仍然使用script1的execfile

更新

如果用execfile是不可能的，那么怎么做呢

Answer 1

MyVar2 = 'value2'

def fun1():
    global MyVar2
    print(MyVar2)

fun1()

实际上，修复需要在脚本2中完成