擅长:python、mysql、java
<p>您已经指定A和B是列表。列表中有可能有重复项在转换为set时丢失</p>
<blockquote>
<p>A set is a collection which is unordered and unindexed. In Python sets
are written with curly brackets.</p>
</blockquote>
<p>为了你的案子你可以</p>
<pre><code>not_processed = filter(lambda x: x in A, B)
</code></pre>
<p>或者</p>
<pre><code>not_processed = [x for x in A if x in B]
</code></pre>
<p>如果x值在B中,上述代码将给出A中存在的所有x值</p>