如何修复模块“…”没有属性“…”

Question

我有第一个模块，它需要打开文件，其中包含娱乐列表：

#testing1
def printEntertainment (venueChoice,entertainmentList,venueList):
    if venueChoice == '1':
        if entertainmentList == '1':
            return('There are no entertainment for VIP Room')

        elif entertainmentList == '2':
            return('There are no entertainment for Executive Room')

        elif entertainmentList == '3':
            return('''
Entertainment for Pool site''')
            x = open('addon/entertainment.txt').readlines()
            desired_lines = [1,2,3]
            output = []
            for desired in desired_lines:
                output.append(x[desired - 1])

            for o in output:
                return("{}.{}".format(output.index(o) + 1, o))

        elif entertainmentList == '4':
            return('''
Entertainment for Banquet Hall''')
            x = open('addon/entertainment.txt').readlines()
            desired_lines = [2,3,4,5]
            output = []
            for desired in desired_lines:
                output.append(x[desired - 1])

            for o in output:
                return("{}.{}".format(output.index(o) + 1, o))

第二个模块是选择娱乐场所和号码：

#testing2
import testing1    
print('''
1.Vip room     2.Executive room
3.pool site    4. Banquet Hall
''')
venueChoice = input('Please select a venue:')
entertainmentList = input('enter no. for entertainment:')
venueList = None
testing2.printEntertainment (venueChoice,entertainmentList,venueList)

choice = testing2.entertainmentList
venueChoice = input('Please enter choice:')
def calculateEntertainment(choice,venueChoice):

    if choice == '1':
        print(0)

    elif choice == '2':
        print(0)

    elif choice == '3':
        if venueChoice == '1':
            print(2000)
        elif venueChoice == '2':
            print(250)
        elif venueChoice == '3':
            print(400)

    elif choice == '4':
        if venueChoice == '1':
            print(250)
        elif venueChoice == '2':
            print(400)
        elif venueChoice == '3':
            print(1000)
        elif venueChoice == '4':
            print(1500)

似乎我不能从printEntertainment (venueChoice,entertainmentList,venueList)使用娱乐列表，我在choice = testing2.entertainmentList使用它。它将打印出module 'testing1' has no attribute 'entertainmentList'。 我应该在程序中添加什么来修复它？谢谢

Answer 1

我觉得你错了很多。您正在从不同的python文件（'testing1.py'）调用函数。因此，要调用函数，它应该是testing1.printEntertainment()，如果要将函数的输出保存为testing2，可以这样做：testing2 = testing1.printEntertainment()。似乎还需要处理类属性之类的变量：testing2.entertainmentList正在尝试从类testing2获取属性entertainmentList，而您从未初始化该属性。所以我建议你再看看一些基本的教程。对于你的代码，你可以把两个文件放在一个文件中，跳过你目前正在做的很多事情。但我不知道你想达到什么目的，所以这里有一些基本的改进，可能会帮助你得到这个想法：

# testing1
def printEntertainment(venueChoice, entertainmentList, venueList):
    if venueChoice == '1':
        if entertainmentList == '1':
            return('There are no entertainment for VIP Room')

        elif entertainmentList == '2':
            return('There are no entertainment for Executive Room')

        elif entertainmentList == '3':
            return('Entertainment for Pool site')
            x = open('addon/entertainment.txt').readlines()
            desired_lines = [1, 2, 3]
            output = []
            for desired in desired_lines:
                output.append(x[desired - 1])

            for o in output:
                return("{}.{}".format(output.index(o) + 1, o))

        elif entertainmentList == '4':
            return('Entertainment for Banquet Hall')
            x = open('addon/entertainment.txt').readlines()
            desired_lines = [2, 3, 4, 5]
            output = []
            for desired in desired_lines:
                output.append(x[desired - 1])

            for o in output:
                return("{}.{}".format(output.index(o) + 1, o))


# testing2
print('''1.Vip room     2.Executive room
3.pool site    4. Banquet Hall''')
# You also should specify what input you want to have (e.g. string or int)
venueChoice = str(input('Please select a venue:'))
entertainmentList = str(input('enter no. for entertainment:'))
venueList = None
testing1 = printEntertainment(venueChoice, entertainmentList, venueList)


def calculateEntertainment(choice, venueChoice):
    if choice == '1':
        print(0)
    elif choice == '2':
        print(0)
    elif choice == '3':
        if venueChoice == '1':
            print(2000)
        elif venueChoice == '2':
            print(250)
        elif venueChoice == '3':
            print(400)
    elif choice == '4':
        if venueChoice == '1':
            print(250)
        elif venueChoice == '2':
            print(400)
        elif venueChoice == '3':
            print(1000)
        elif venueChoice == '4':
            print(1500)


calculateEntertainment(entertainmentList, venueChoice)