如何处理pyspark数据帧或RDD中n个行

2024-10-01 05:04:41 发布

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有火花王吗

用例:我有一个100万行的数据帧,我希望一次处理5行json而不失去并行性

数据帧(df)示例:

+-------------+---------+
|    col_a    |  col_b  |
+-------------+---------+
| row1a       | row1b   |
| row2a       | row2b   |
| row3a       | row3b   |
| row4a       | row4b   |
| row5a       | row5b   |
| row6a       | row6b   |
| row7a       | row7b   |
| ..          | ..      |
+-------------+---------+

当前工作方案

zipwithindex公司

row_id_df = df.rdd.map(lambda x: json.dumps(x.asDict())).zipWithIndex().toDF(["item", "id"])

上一行将数据帧转换为

数据帧(行\u id \u df):

+--------------------------------------+--------+
|                    item              |   id   |
+--------------------------------------+--------+
| {"col_a": "row1a", "col_b": "row1b"} |   0    |
| {"col_a": "row2a", "col_b": "row2b"} |   1    |
| {"col_a": "row3a", "col_b": "row3b"} |   2    |
| {"col_a": "row4a", "col_b": "row4b"} |   3    |
| {"col_a": "row5a", "col_b": "row5b"} |   4    |
| {"col_a": "row6a", "col_b": "row6b"} |   5    |
| {"col_a": "row7a", "col_b": "row7b"} |   6    |
| ..                                   | ..     |
+--------------------------------------+--------+

到目前为止,我已经有了所有id为的行,现在我使用表达式groupby将每5个项目分组到一个组中

splitBy = (floor(col("id") / lit(5)) * lit(5)) \
                   .cast(IntegerType()).alias("id")

row_id_df.groupBy(splitBy) \
            .agg(collect_list(col("item"))) \
            .select(col("collect_list(item)").alias("items")) \
            .rdd.foreach(process_each_5)

process_each_5(data):
    print(len(data.items)) // 5

我能做到这一点,工作非常好。但是,我觉得还有一种更简单的方法

最后,我需要结束上面的解释:

发件人:

+-------------+---------+
|    col_a    |  col_b  |
+-------------+---------+
| row1a       | row1b   |
| row2a       | row2b   |
| row3a       | row3b   |
| row4a       | row4b   |
| row5a       | row5b   |
| row6a       | row6b   |
| row7a       | row7b   |
| ..          | ..      |
+-------------+---------+

收件人:

+-------------------------------------------+
|                    items                  |
+-------------------------------------------+
| [{"col_a": "row1a", "col_b": "row1b"},    |
|  {"col_a": "row2a", "col_b": "row2b"},    |
|  {"col_a": "row3a", "col_b": "row3b"},    |
|  {"col_a": "row4a", "col_b": "row4b"},    |
|  {"col_a": "row5a", "col_b": "row5b"}]    |
| [{"col_a": "row6a", "col_b": "row6b"},    |
|  {"col_a": "row7a", "col_b": "row7b"},...]|
| ..                                        |
+-------------------------------------------+

PS:我不想使用df.collect()


Tags: 数据iddfcolrow1arow1brow4arow4b