[[[12, 71.2989367, -156.7286143, Samuel Simmonds Memorial Hospital, 4], [4, 64.8311569, -147.7399471, Fairbanks Memorial Hospital, 4].1, [6, 64.4993412, -165.3776787, Norton Sound Regional Hospital, 4].2, [5, 61.56316029999999, -149.2576383, Mat-Su Regional Medical Center, 4]]
需要将其转换为数据帧上的内容:
ID Lat Long Name Level
12, 71.2989367, -156.7286143, Samuel Simmonds Memorial Hospital, 4
4, 64.8311569, -147.7399471, Fairbanks Memorial Hospital, 4
6, 64.4993412, -165.3776787, Norton Sound Regional Hospital, 4
常规的
DataFrame
构造函数应该做到这一点,但请记住,您的数据有一些错误.
是一个3级嵌套列表(因此您需要使用[0]访问它)输出:
很简单。引用字符串,删除列表中的额外级别
结果:
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