擅长:python、mysql、java
<p>不知道你试过什么。这应该以同样的方式工作:</p>
<pre><code>arr = [2,2,2,2,4,5,2,45,3,4,4]
mostFrq = 0
mostFrqAmount = 0
for i in arr:
amountOfCurrent = 0
# now look at temp element
for j in arr:
if (j == i):
amountOfCurrent = amountOfCurrent + 1
if (amountOfCurrent > mostFrqAmount):
mostFrqAmount = amountOfCurrent
mostFrq = i
print(mostFrq)
print(mostFrqAmount)
</code></pre>