我有这样一个json数据:
{
"children": [{
"objName": "Sprite1",
"scripts": [[89, 68, [["whenGreenFlag"], ["doForever", [["doIf", ["keyPressed:", "space"], [["wait:elapsed:from:", 0.5], ["playSound:", "meow"]]],
["doIf", ["mousePressed"], [["playDrum", 1, 0.25]]]]]]]],
"sounds": [{
"soundName": "meow",
"soundID": 0,
"md5": "83c36d806dc92327b9e7049a565c6bff.wav",
"sampleCount": 18688,
"rate": 22050,
"format": ""
}],
}
}
我想计算“脚本”下出现“按键”的次数。但是我不知道如何遍历列表。。。。在“脚本”下。你知道吗
这是我的密码:
import simplejson as json
with open("D:\\1.SnD\Work\PyCharmProjects\project.json", 'rb') as f:
json_data = json.loads(str(f.read(), 'utf-8'))
key_presses = []
for child in json_data.get('children'):
for script in child.get('scripts'):
for mouse in script.get("keyPressed"): // Does not work
print(mouse)
我想在按键列表中存储按键次数。你知道吗
借用What is the fastest way to flatten arbitrarily nested lists in Python?中优秀的
flatten
方法并将其与集合中的Counter
相结合,可以得到:如果运行上述命令,输出将是
keyPressed:
在脚本中出现的次数。你知道吗相关问题 更多 >
编程相关推荐