如何在while循环中修复索引错误（列表）如果它只出现在while循环中

Question

我的问题是，我有一个数字列表，如果试图将列表中的每个元素保存在一个变量中以拆分它们，那么我得到的错误列表索引超出了范围。但如果我尝试whithoul和wihle loup，并对列表中的2或3个元素手动执行，它就可以工作了。你知道吗

我在stackoverflow和reddit上尝试了很多不同的可能性，但是northing成功了。你知道吗

import itertools
from itertools import combinations
from itertools import permutations
from itertools import combinations_with_replacement

f = 2, 'f'
u = 3, 'u'
th = 5, 'th'
o = 7, 'o'
r = 11, 'r'
c = 13, 'c/k'
g = 17, 'g'
w = 19, 'w'
h = 23, 'h'
n = 29, '29'
i = 31, 'i'
j = 37, 'j'
s = 53, 's/z'
t = 59, 't'
b = 61, 'b'
e = 67, 'e'
m = 71, 'm'
l = 73, 'l'
ng = 79, 'ng/ing'
oe = 83, 'oe'
d = 89, 'd'
a = 97, 'a'
ae = 101, 'ae'
y = 103, 'y'
eo = 41, 'eo'
p = 43, 'p'
x = 47, 'x'
ia = 107, 'ia,io'
ea = 109, 'ea'


runen = [f, u, th, o, r, c, g, w, h, n, i, j, s, t, b, e, m, l, ng, oe, d, a, ae, y, eo, p, x, ia, ea]

runen1 = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 43, 47, 107, 109]
kek = list(combinations(runen1, 2))
zero = 0
null = 0
while(zero < len(kek)):
    jayjay = kek[null]
    jayjay1 = jayjay.replace(',', '')
    jayjay1 = jayjay.replace("'", '')
    jayjay1 = jayjay.replace('(', '')
    jayjay1 = jayjay.replace(')', '')
    jayjay1 = jayjay.replace(' ', '')
    newlist = []
    newlist.append(jayjay)
    del kek[null]
    null = null +1

print(newlist)

我将新列表导出为输出 但是输出是错误的：列表索引超出范围

Answer 1

你把事情弄得太复杂了。使用列表理解：

import itertools
runen1 = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 43, 47, 107, 109]
newlist = [int(str(a) + str(b)) for a,b in itertools.combinations(runen1,2)]

如果你想从2推广。您可以使用：

def kspots(nums,k):
    return [int(''.join(str(a) for a in c)) for c in itertools.combinations(nums,k)]

然后，例如，kspots(runen1,17)将是您似乎想要的（大）列表。这个列表有21474180个元素，在我的机器上生成要花一分钟的时间，所以您可能希望使用生成器表达式而不是列表理解（用(,)替换外部的[,]）