正则表达式：匹配任意单词前面任意数量的副词

Question

我有一组字符串，其形式如下，X表示任意单词

This is a string ((X.address)) test
This is a string ((X address)) test
This is a string (X address) test
This is a string (X.address) test

一旦X.address或X address被找到（包括前面的paranethes），我就要删除字符串的所有内容

This is a string
This is a string
This is a string
This is a string

这是我的出发点：

regex = r"\(X.address"
s = "This is a string ((X.address)) test"
re.split(regex, s)[0]

>> 'This is a string ('

它是有效的，但我需要对它进行概括，以便它搜索任意单词而不是X，并考虑单词前面的一个或多个偏执词。你知道吗

Answer 1

你可以用

re.sub(r'\s*\(+[^()]*\baddress.*', '', s, flags=re.S)

细节

• \s*-0+空格
• \(+-1+(字符
• [^()]*-除(和)之外的任何0+字符
• \b-单词边界（address前面不能有其他字母、数字或下划线）
• address-一个单词
• .*-字符串末尾的任何0+个字符。你知道吗

参见Python demo：

import re
strs = [ 'This is a string ((X.address)) test', 'This is a string ((X address)) test', 'This is a string (X address) test', 'This is a string (X.address) test', 'This is a string ((X and Y and Z address)) test' ]
for s in strs:
    print(s, '=>', re.sub(r'\s*\(+[^()]*\baddress.*', '', s, flags=re.S))

输出：

This is a string ((X.address)) test => This is a string
This is a string ((X address)) test => This is a string
This is a string (X address) test => This is a string
This is a string (X.address) test => This is a string
This is a string ((X and Y and Z address)) test => This is a string

Answer 2

你可以.+(?=\s\(+X(?:\.|\s)address)

说明：

.+-匹配一个或多个字符

(?=...)-正面展望

\s-空白

\(+-匹配一个或多个(

X-按字面意思匹配X

(?:...)-非捕获组

\.|\s-匹配点.或空格

address-按字面意思匹配address

Demo

Answer 3

使用

regex = r"(This is a string)\s+\(+.+\)"
s = "This is a string ((X.address)) test"
re.split(regex, s)[1]