有人能帮我搞定康威和李的比赛吗

Question

我使用的是python3.6。我已经快速浏览了google和stack overflow，但是我还没有看到一个关于我的问题。问题是，我的函数应该查找活动邻居的数量，但返回了错误的值（但只是有时）。你知道吗

代码如下：

def neighbourCount(i, j):
    neighbours = 0

    try:
        if grid[i-1][j-1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i-1][j] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i-1][j+1] == "1":
            neighbours +=1
    except:
        pass

    try:
        if grid[i][j-1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i][j+1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i+1][j-1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i+1][j] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i+1][j+1] == "1":
            neighbours +=1
    except:
        pass

    return(neighbours)



grid = [
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","1","0","0","0","0","0","0","0"],
    ["0","0","1","0","0","0","0","0","0","0"],
    ["0","0","1","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"]
    ]

newGrid = [
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"]
    ]


game = 1
while game == 1:

    for i in range(0,10):
        print(*grid[i], sep='  ')

    numNeigh = []

    for i in range(0,10):
        row = []
        for j in range(0,10):
            neighbours = neighbourCount(i, j)
            if grid[i][j] == "1" and ( neighbours>1 and neighbours<4 ):
                newGrid[i][j] = "1"
            if grid[i][j] == "1" and ( neighbours<2 or neighbours>3 ):
                newGrid[i][j] = "0"
            if grid[i][j] == "0" and neighbours == 3:
                newGrid[i][j] = "1"
            row.append(neighbours)

        numNeigh.append(row)

    for i in numNeigh:
        print(i)
    for i in newGrid:
        print(i)

    print("\n\n")

    grid = newGrid

    input()

这是输出（第一块：网格数组）（第二块：每个单元格的邻居）（第三块：newGrid数组）：

0  0  0  0  0  0  0  0  0  0 
0  0  0  0  0  0  0  0  0  0
0  1  1  1  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[1, 2, 3, 3, 2, 0, 0, 0, 0, 0]
[1, 2, 4, 2, 2, 0, 0, 0, 0, 0]
[1, 1, 2, 1, 1, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '1', '1', '0', '0', '0', '0', '0', '0']
['0', '1', '0', '1', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']

（注意：我还有一个用于“newGrid”的2D数组，它与“grid”相同，但只有“0”）

中间的区块显示每个位置的邻居数量，但不是在第三行显示“1，1，2，1，1，0，0…”，而是显示“1，2，4，2，2，0，0…”

Answer 1

您的问题可能在于创建newGrid的行。除非正确地创建grid（深度副本）的副本，否则元素将指向相同的列表（浅层副本）。所以当你改变newGrid时，grid也在改变。要正确创建grid的副本，请将newGrid行更改为：

newGrid = grid.copy()

收件人：

newGrid = [x[:] for x in grid]

---

注意：使用numpy将在调用numpy数组的copy方法时自动创建适当的深度副本。