擅长:python、mysql、java
<pre><code>def same_father(me, data):
hasdad = data.Father == data.at[me, 'Father']
notme = data.index != me
isbro = hasdad & notme
return data.loc[isbro].index.tolist()
df2 = df.set_index('Name')
getbro = lambda x: same_father(x.name, df2)
df2['Brother'] = df2.apply(getbro, axis=1)
</code></pre>
<p>我认为这应该行得通</p>