我想用python把数据保存在字典里。有不同的点(x,y),每个点有不同的数据。你知道吗
import pprint
d=dict()
start = ((1, 3), "<Direction.NORTH: 0>")
target = ((0, 3), "<Direction.WEST: 270>")
weight = 666
startt = ((1, 3), "<Direction.WEST: 270>")
targett = ((0, 3), "<Direction.WEST: 270>")
weightt = 777
starttt = ((2, 3), "<Direction.NORTH: 0>")
targettt = ((0, 3), "<Direction.WEST: 270>")
weighttt = 888
d[start[0]] = {start[1]:(target, weight)}
d[startt[0]] = {startt[1]: (targett, weightt)}
d[starttt[0]] = {starttt[1]:(targettt, weighttt)}
pp = pprint.PrettyPrinter()
pp.pprint(d)
Python用第二个点覆盖第一个点,因为该点已经存在于dict中。如何实现Python在dict中比较dict的键? 输出:
{(1, 3): {'<Direction.NORTH: 0>': (((0, 3), '<Direction.WEST: 270>'), 777)},
(2, 3): {'<Direction.NORTH: 0>': (((0, 3), '<Direction.WEST: 270>'), 888)}}
输出应该是这样的:
{
(0, 3): {
Direction.NORTH: ((0, 3), Direction.WEST, 1),
Direction.EAST: ((1, 3), Direction.WEST, 2)
},
(1, 3): {
Direction.WEST: ((0, 3), Direction.EAST, 2),
...
},
目前没有回答
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