两个int对象之间的条件检查

Question

我在for循环中迭代，构造一个列表，同时将该列表的最后一个数字与另一个数字进行比较。你知道吗

我想让我的代码查看列表的最后一项是否比它要比较的项小，如果是，则将其添加到列表的末尾，然后继续。你知道吗

如果列表的最后一项较大，我想弹出列表的最后一项。那么，我想对其附加同样的条件。你知道吗

这是我的代码，它不工作，它不会重新检查后弹出列表的最后一项条件。你知道吗

if tempList:
    lastNum=tempList[-1]
    #############################################
    if element < lastNum:
        incList.append(tempList)
        tempList.pop()
        lastNum=tempList[-1]
   #############################################

    elif lastNum < element:                                               
        tempList.append(element)
        continue

Answer 1

您可以将其捆绑到一个函数中：

def append_if_lower_else_pop_end_from_list_until_lower(l, num):
    """Add num to l if l[-1] < num, else pop() from l until"""
    while l and l[-1] > num:
        l.pop()
    l.append(num)

    # this is not strictly needed - lists are mutable so you are mutating it
    # returning it would only make sense for chaining off it with other methods
    return l 

k = [3,5,7,9,11,13]
print(k)
append_if_lower_else_pop_end_from_list_until_lower(k, 10)
print(k)
append_if_lower_else_pop_end_from_list_until_lower(k, 6)
print(k)
append_if_lower_else_pop_end_from_list_until_lower(k, 10)
print(k)
append_if_lower_else_pop_end_from_list_until_lower(k, 10)
print(k)
append_if_lower_else_pop_end_from_list_until_lower(k, -10)
print(k)

输出：

[3, 5, 7, 9, 11, 13]  # start
[3, 5, 7, 9, 10]      # after adding 10
[3, 5, 6]             # after addding 6
[3, 5, 6, 10]         # after adding 10
[3, 5, 6, 10, 10]     # after adding 10 again
[-10]                 # after adding -10 

---

为什么还要返回列表：链接示例：

k = [3,5,17,9,11,13]
append_if_lower_else_pop_end_from_list_until_lower(k, 10).sort()
print(k)

输出：

[3, 5, 9, 10, 17]

Answer 2

试试这个：

yourlist = [3,1,4]
n = 1
resultlist = yourlist[:-1] if yourlist[-1]>=n else yourlist+[n]
print(resultlist)
n = 5
resultlist = yourlist[:-1] if yourlist[-1]>=n else yourlist+[n]
print(resultlist)

输出： [3,1]

[3,1,4,5]