我在JSON文件中有一个对象数组。如果一个单词不在对象内的值中,我想删除整个对象。你知道吗
for x in results:
if "Berline" in auction_type.split():
if any(word in auction_model for word in berlinewords):
del x
else:
pass
else:
pass
不起作用。你知道吗
数据库示例:
"objectID": 11460,
"type": "Coupé",
"cars_getroute": "bugatti-type-57-stelvio-cabriolet-1934-1936",
"gm_url": "https://www.url.com",
"results": [
{
"marque": "Bugatti",
"model": "Type 57 Stelvio",
"model_year": "1936",
"price_str": "Estimate $900 000 - $1 200 000 (unsold)",
"price_int": null,
"price_currency": null,
"sold": false,
"auction_house": "RM Sotheby's",
"auction_country": "USA",
"auction_date": "12 mars 2016",
"auction_datetime": "2016-03-12",
"auction_url": null,
"image_urls": "https://www.url.com",
"price_int_eu": null
}
]
如果单词“Berline”在“type”中,而另一个在“model”中的其他单词列表中,我想删除这个对象(在示例中只是“results”:[])
当我尝试用一个随机值替换model的值时,它工作得很好,但是我不能删除整个对象。你知道吗
遍历
results
的副本:相关问题 更多 >
编程相关推荐