擅长:python、mysql、java
<p>您可以<code>join</code>不是<code>None</code>的值:</p>
<pre><code>keys = ["[zipcode]", "[street_name]", "[primary_number]",
"[secondary_number]", "[street_predirection]", "[street_postdirection]",
"[street_suffix]"]
d['AddressStr'] = ' '.join([d[key] for key in keys if d[key] is not None])
</code></pre>