擅长:python、mysql、java
<p>可能不是最聪明的解决方案,但您可以通过两个类似于<a href="https://stackoverflow.com/a/5347492/1258041">this answer</a>的过程来完成:</p>
<pre><code>In [1]: import numpy as np
In [2]: s = np.array([1, 2] * 3)
In [3]: b = np.zeros(2 * s.size)
In [4]: b[2::4] = s[::2]
In [5]: b[3::4] = s[1::2]
In [6]: b
Out[6]: array([ 0., 0., 1., 2., 0., 0., 1., 2., 0., 0., 1., 2.])
</code></pre>