python：没有输出或者只生成了一个空列表

Question

index1 = 0
singlechar = []
def SINGLE_CHAR_VAR(filename):
    firdict = vars_indents(filename)[0]
    firtup_keys = firdict.keys()
    firtup_val = firdict.values()
    for keys in firtup_keys:
        for values in firtup_val:
            index = 0
            for index in range(len(values)):
                firvallist = firtup_val[index]
                for item in firvallist:
                    if len(item[0]) == 1:
                        singlechar.append({'ERROR_TYPE': 'SINGLE_CHAR_VAR', 'LINE_NUMBER': str(keys),'COLUMN': str(item[1]),'INFO': str(item[0]),'SOURCE_LINE': str(lines[keys - 1])})
                    else:
                        continue
                return singlechar

这是我的代码，但是没有生成输出，或者当我在return语句周围移动时，生成了一个空列表。我希望它能给我一个字典列表作为输出。你知道吗

有人能教我怎么修吗？你知道吗

谢谢

Answer 1

我认为问题出在返回语句中。应该将return语句缩进外部for循环的正下方，而不是内部for循环的正下方。具体如下：

def SINGLE_CHAR_VAR(filename):
    firdict = vars_indents(filename)[0]
    firtup_keys = firdict.keys()
    firtup_val = firdict.values()
    for keys in firtup_keys:
        for values in firtup_val:
            index = 0
            for index in range(len(values)):
                firvallist = firtup_val[index]
                for item in firvallist:
                    if len(item[0]) == 1:
                        singlechar.append({'ERROR_TYPE': 'SINGLE_CHAR_VAR', 'LINE_NUMBER': str(keys),'COLUMN': str(item[1]),'INFO': str(item[0]),'SOURCE_LINE': str(lines[keys - 1])})
                    else:
                        continue
    return singlechar # indent of return changed