<p>下面是一个我认为您希望通过递归实现的最小示例—通常每次都使用相同的值,但可以灵活地更改其中的一些值。这是你想要的吗?你知道吗</p>
<p>关键的一点是获取args/kwargs的副本,否则您将在任何时候更改某些内容时为每个未完成的调用修改args/kwargs。你知道吗</p>
<p>你可以用一个自动提供原件和复印件的装饰器来装饰它,也许甚至不必分出当前的名字。你知道吗</p>
<pre><code>def factorial(*args_this_call, **kwargs_this_call):
print(' -'
'\nargs: {}'
'\nkwargs: {}'.format(args_this_call, kwargs_this_call))
# get copies so you don't modify the values of other calls that are waiting to complete
args_next_call = list(args_this_call)
kwargs_next_call = kwargs_this_call.copy()
# you can break out the content of args / kwargs for clarity if you are going to use them a lot
arg1, arg2 = args_this_call # not used - just for example
n = kwargs_this_call['n']
# do your work
if n == 1:
return 1
else:
# modify whichever args/kwargs you want, leave the ones you don't want to change
args_next_call[1] += 1 # some random modification
kwargs_next_call['call_id'] += 1
kwargs_next_call['n'] -= 1 # n-1 for factorial in this case
# make the call
result = n * factorial(*args_next_call, **kwargs_next_call)
return result
# test the factorial with args/kwargs
args = (1, 1) # just some values
kwargs = {'call_id': 1,
'n': 4}
print(factorial(*args, **kwargs))
</code></pre>
<p>结果:</p>
<pre><code> -
args: (1, 1)
kwargs: {'call_id': 1, 'n': 4}
-
args: (1, 2)
kwargs: {'call_id': 2, 'n': 3}
-
args: (1, 3)
kwargs: {'call_id': 3, 'n': 2}
-
args: (1, 4)
kwargs: {'call_id': 4, 'n': 1}
24
</code></pre>